3sin^2x+3cos^2x=4x-5

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Solution for 3sin^2x+3cos^2x=4x-5 equation:


Simplifying
3sin2x + 3cos2x = 4x + -5

Reorder the terms:
3cos2x + 3in2sx = 4x + -5

Reorder the terms:
3cos2x + 3in2sx = -5 + 4x

Solving
3cos2x + 3in2sx = -5 + 4x

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3in2sx' to each side of the equation.
3cos2x + 3in2sx + -3in2sx = -5 + -3in2sx + 4x

Combine like terms: 3in2sx + -3in2sx = 0
3cos2x + 0 = -5 + -3in2sx + 4x
3cos2x = -5 + -3in2sx + 4x

Divide each side by '3os2x'.
c = -1.666666667o-1s-2x-1 + -1in2o-1s-1 + 1.333333333o-1s-2

Simplifying
c = -1.666666667o-1s-2x-1 + -1in2o-1s-1 + 1.333333333o-1s-2

Reorder the terms:
c = -1in2o-1s-1 + 1.333333333o-1s-2 + -1.666666667o-1s-2x-1

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